使用梅校的算法

app/excel_parse.py

@@ -22,6 +22,14 @@ EXAM_HINT = re.compile(
     re.I,
 )
 SKIP_SHEETS = ("说明", "readme", "目录")
+
+
+def _is_skip_sheet(name: str) -> bool:
+    n = name.lower()
+    if any(x in n for x in SKIP_SHEETS):
+        return True
+    return "概率分析" in n or "指标数" in n
+
 ART_RE = re.compile(r"艺术|体育|艺体")
 LEAVE_RE = re.compile(r"请假|出国|休学|国际|不在校|港澳|港籍.*假")
 
@@ -76,6 +84,8 @@ def parse_workbook(path: Path | BytesIO) -> dict:
 
     for ws in wb.worksheets:
         kind = _sheet_kind(ws.title)
+        if _is_skip_sheet(ws.title):
+            continue
         rows = ws.iter_rows(values_only=True)
         try:
             header_row = next(rows)
@@ -201,7 +211,7 @@ def summarize_parse(parsed: dict) -> dict:
     tracks = {}
     classes = {}
     status = {}
-    art = leave = 0
+    art = leave = moves = 0
     exam_present = {e: 0 for e in exams}
     for s in students:
         tracks[s["track"] or "未分方向"] = tracks.get(s["track"] or "未分方向", 0) + 1
@@ -211,6 +221,8 @@ def summarize_parse(parsed: dict) -> dict:
             art += 1
         if s["leave"]:
             leave += 1
+        if (s.get("move") or "").strip() or s.get("sheet_kind") in ("art", "leave"):
+            moves += 1
         for e in exams:
             if s["scores"].get(e) is not None:
                 exam_present[e] += 1
@@ -236,6 +248,7 @@ def summarize_parse(parsed: dict) -> dict:
         "status": status,
         "art": art,
         "leave": leave,
+        "moves": moves,
         "exam_present": exam_present,
         "score_scale": score_scale,
         "sheets": parsed["sheets"],